Three electric cells each of e.m.f 1.5V and internal resistance of 1.0(Omega) are connected in parallel across an external resistance of (frac{2}{3})(Omega). Calculate the value of the current in the resistor
-
A.
0.5 A -
B.
0.9A -
C.
1.5A -
D.
4.5A
Correct Answer: Option C
Explanation
E.m.f = 1.5
r = (frac{1 times 1 times 1}{(1 times 1) + (1 times 1) + (1 times 1)})
r = (frac{1}{3})(Omega)
I = (frac{E.m.f}{r + R})
I = (frac{1.5}{frac{1}{3} + frac{2}{3}})
I = 1.5A