A 12V battery has an internal resistance of 0.5W.If a cable of 1.0W resistance is connected across the two terminals of the battery, the current drawn from the battery is
-
A.
16.0A -
B.
8.0A -
C.
0.8A -
D.
0.4A
Correct Answer: Option B
Explanation
I = (frac{E.m.f}{R + r})
= (frac{12}{1 + 0.5})
I = 8A