Given that (frac{1}{8^{2y – 3y}} = 2^{y + 2}).

Correct Answer: Option C

Explanation

(frac{1}{8^{2y – 3y}} = frac{1}{8^{-y}} = 8^{y})

(8^{y} = 2^{y + 2} implies (2^{3})^{y} = 2^{y + 2})

(3y = y + 2 implies 2y = 2)

(y = 1)