If 0.2g of a salt is required to saturate 200(cm^{3}) of water at room temperature, what is the solubility of the salt?
-
A.
0.2(gdm^{-3}) -
B.
1.0(gdm^{-3}) -
C.
2.0(gdm^{-3}) -
D.
5.0(gdm^{-3})
Correct Answer: Option B
Explanation
Solubility in (gdm^{-3}) = (frac{mass of salt in gram}{volume of liquid in dm^{3}})
200(cm^{3}) = (frac{200}{1000} dm^{3} = 0.2dm^{3})
Solubility = (frac{0.2g}{0.2dm^{3}})
= 1.0(gdm^{-3})