A fixed mass of gas of volume 600cm3 at a temperature of 27oC is cooled at constant pressure to a temperature of 0oC. What is the change in volume?
-
A.
54cm2 -
B.
273cm2 -
C.
300cm2 -
D.
546cm2 -
E.
600cm2
Correct Answer: Option A
Explanation
(frac{V_1}{T_1} = frac{V_2}{T_2})
T2 = 0 + 273 = 273k
V1 = 600
T1 = 27 + 273 = 300k
V2 = (frac{V_1T_2}{T_1}) = 546cm
V1 – V2 = 54cm