Water of mass 120g at 50oC is added to 20og of water at 10oC and the mixture is well stirred. Calculate the temperature of the mixture. [Neglect heat losses to the surrounding]
-
A.
60oC -
B.
40oC -
C.
25oC -
D.
10oC
Correct Answer: Option C
Explanation
120 x 4.2(50 – (theta)) = 200 x 4.2((theta) – 10)
(theta = frac{33600}{1344} = 25^oC)