16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3
[Pb = 207, N = 14, O = 16]
-
A.
0.05 g -
B.
2.00 g -
C.
1.00 g -
D.
0.50g
Correct Answer: Option D
Explanation
molar mass of pb (N0 3) 2 = 331
Mole = (frac{16.55}{331})= 0.05 mole
∴0.05mole pb (No3)2 dissolved in 1000g H2O x = (frac{0.05times1000}{100})= 0.5 mole /dm 3
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