What number of moles of Cu 2+ will be deposited by 360 coulombs of electricity?
[f = 96500 C mol -1]
-
A.
5.36 x 10 -4 mole -
B.
1. 87 x 10 10 -3 mole -
C.
9. 35 x 10 -4 mole -
D.
3. 73 x 10 -3
Correct Answer: Option B
Explanation
Cu(^{2+}) + 2e(^{-})(_{(aq)}) (rightarrow) Cu(_{(s)})
Liberating 1 mole of Cu
2 x 1F = 2 x 96,500C = 193,000C of electricity is needed
Hence, 193,000C = 1 mole
360C of electricity = (frac{360C times 1 mol}{193,000C})
= 0.001865 mol
= 1.87 x 10(^{-3}) moles
There is an explanation video available below.