What is the derivative of t2 sin (3t – 5) with respect to t?
-
A.
6t cos (3t – 5) -
B.
2t sin (3t – 5) – 3t2 cos (3t – 5) -
C.
2t sin (3t – 5) + 3t2 cos (3t – 5) -
D.
2t sin (3t – 5) + t2 cos 3t
Correct Answer: Option C
Explanation
t2 sin (3t – 5) = 2t sin ( 3t – 5) + t2 x 3 cos (3t – 5) = 2t sin (3t – 5) + 3t2 cos (3t – 5).
Detailed answer below was provided by Ifechuks, a female prospective student of Okopoly.