Two strings of the same length and under the same tension gives notes of frequencies in the ratio 4 : 1. The masses of the strings are in the corresponding ratio of
-
A.
2 : 1 -
B.
1 : 2 -
C.
1 : 4 -
D.
1 : 16
Correct Answer: Option D
Explanation
F = (frac{1}{2L})(sqrtfrac{T}{m})
(frac{F_1}{F_2}) = (sqrtfrac{m_2}{m_1})
(frac{1}{4}) = (sqrtfrac{m_2}{m_1})
(sqrtfrac{m_2}{m_1}) = (frac{1}{16})