Two balls X and Y weighing 5 g and 50 kg respectively were throne up vertically at the same time with a velocity of 100 ms1 .How will their positions be one second later?
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A.
X and Y will be 500 m from each other -
B.
Y will be 500 m ahead of X -
C.
X will be 500 m ahead of Y -
D.
X and Y both be 500 m from the poin of throw
Correct Answer: Option D
Explanation
v2 = U2 – 2G s
0 = 1002 – 2 x 10 x s = 10000 – 20s
s = (10000)/20 = 500m
Which is independent of mass.the two bodies where acted upon by the same retarding force of gravity which is independent of mass of the body; therefore both will be 500 m from the point of throw.