the pressure of 3 moles of an ideal gas at a temperature of 27°C having a volume of 10-3m3 is
-
A.
2.49 x 105Nm-2 -
B.
7.47 x 105Nm-2 -
C.
2.49 x 106Nm-2 -
D.
7.47 x 106Nm-2
Correct Answer: Option D
Explanation
From the relation PV = nRT
V = 10-3m3; n = 3 moles; T = 27 + 273 = 300k
R = 8.3 j mol-1 K-1
=> P = nRT/V = 3 X 8.3 X 300/10-3 = 7.47 X 106 Nm-2