The number of atoms of chlorine present in 5.85g of NaCl is [Avogaro’s Number =…

The number of atoms of chlorine present in 5.85g of NaCl is [Avogaro’s Number = 6.02 x 1023]
  • A.
    6.02 x 1022
  • B.
    5.85 x 1023
  • C.
    6.02 x 1023
  • D.
    5.85 x 1024
Correct Answer: Option A
Explanation

The number of atoms of chloride present in 5.85g of NaCl is 5.85 x 6.0 x 1023
= 6.02 x 1022

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