The latent heat of fusion of ice is 80cal g-1. How much heat is required to change 10g of ice at QoC into water at the same temperature?
-
A.
80 cal -
B.
10 cal -
C.
8 cal -
D.
800 cal -
E.
400 cal
Correct Answer: Option D
Explanation
Quantity of heat = ml
= 10 x 80
= 800 cal