The horizontal component of the initial speed of a particle projected at 30° to the horizontal is 50 ms(^{-1}). If the acceleration cf free fall due to gravity is 10ms(^{-2}), determine its: (a) initial speed; (b) speed at maximum height reached.
Explanation
(a) If initial velocity = U Then horizontal component
(U_x = Ucostheta)
Ucos(theta) = 50
U = (frac{50}{cos theta} = frac{50}{cos 30^o}) = 57.7m/s
(b) But at maximum height V = O
V(_y) = O
V(_x) = U(_x) = 50m/s