The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
-
A.
0.05kg -
B.
0.20kg -
C.
0.80kg -
D.
1.00kg
Correct Answer: Option A
Explanation
M(_r)(90 – 50) = 0.2(100 – 90)
40M(_r) = 0.2 × 10
| M(_r) | = | 2
40 |
= | 0.05kg |
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