The density of a body is (5times10^3kgm{^-3}) and it weighs 1N in air. Calculate the apparent weight of the body when totally immersed in water. (Density of water =(10^3kgm{-3}, g= 10ms^{-2}
-
A.
0.02N -
B.
0.08N -
C.
0.20N -
D.
0.80N -
E.
1N
Correct Answer: Option D
Explanation
Upthrust = weight of the water displaced =pvg= 1000 x 2 x (10^{-5})=0.20N \ Apparent weight = weight in air – upthrust = 1-0.2N=0.8N