Answers

simplify; 2log(_{3}) 6 + log(_{3}) 12 – log(_{3}) 16

simplify; 2log(_{3}) 6 + log(_{3}) 12 – log(_{3}) 16

A.
2
B.
3
C.
2 – 2log₃2
D.
3 – log₃2
E.
4 – log₃2

Correct Answer: Option B

Explanation

2log(_{3}) 6 + log(_{3}) 12 – log(_{3}) 16

= (log_3 6^2 + log_3 12 – log_3 16)

= (log_{3} (frac{36 times 12}{16}))

= (log_{3} (27))

= (log_{3} 3^3)

= (3 log_{3} 3)

= 3