In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.
-
A.
70o -
B.
55o -
C.
40o -
D.
35o
Correct Answer: Option B
Explanation
PQRS is a cyclic quad^P = 180 – 110 (opp ∠s of a cyclic quad)^P = 70
In ΔPTS, ^S = ^T (base ∠s of Isc Δ)
∴^T = (180-70) / 2
= 110/2
= 55o
But ^T x(corr ∠)
∴x =55