In the diagram, QR//ST, /PQ/ = /PR/ and In the diagram, QR//ST, /PQ/ = /PR/ and o. Find the value of y A. 105o B. 110o C. 130o D. 150o Correct Answer: Option A Explanation In (bigtriangleup) PQR, Q = S = 75o (Corresponding angle) R = Q = 75o (Base angles of an isosceles (bigtriangleup)) But, y + 75o = 180o (Sum of angles in a straight line) y = 180 – 75 y = 105o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }}

In the diagram, QR//ST, /PQ/ = /PR/ and o. Find the value of y
  • A.
    105o
  • B.
    110o
  • C.
    130o
  • D.
    150o
Correct Answer: Option A
Explanation

In (bigtriangleup) PQR,
Q = S = 75o (Corresponding angle)
R = Q = 75o (Base angles of an isosceles (bigtriangleup))
But, y + 75o = 180o (Sum of angles in a straight line)
y = 180 – 75
y = 105o

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