In the diagram, MQ//RS, In the diagram, MQ//RS, o and o. Find the value of x A. 150o B. 110o C. 100o D. 95o Correct Answer: Option C Explanation L + 30o – 180o(Sum of L = 180o – 30o = 150o L = q = 150o(opposite y = b = 30o(alt. b + c = 180o(sum of 30o + c 180 c = 180 – 30 c = 150o b = a = 30o (opp c = d = 150o (opp a + k + 70o = 180o (sum of 30o + k + 70o = 180 k + 100o = 180 k = 180 – 100 k = 80o x + 80o = 180(sum of x = 180o – 80o x = 100o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}: {{ reply.created_at }}

In the diagram, MQ//RS, o and o. Find the value of x

L + 30^o – 180^o(Sum of

L = 180^o – 30^o = 150^o
L = q = 150^o(opposite

y = b = 30^o(alt.

b + c = 180^o(sum of

30^o + c 180
c = 180 – 30
c = 150^o
b = a = 30^o (opp

c = d = 150^o (opp

a + k + 70^o = 180^o (sum of

30^o + k + 70^o = 180
k + 100^o = 180
k = 180 – 100
k = 80^o
x + 80^o = 180(sum of

x = 180^o – 80^o
x = 100^o

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