In the diagram, (bar{OX}) bisects In the diagram, (bar{OX}) bisects o, calculate the value of A. 68o B. 72o C. 112o D. 124o Correct Answer: Option D Explanation In (Delta) XYZ, 2m + 2n + 68o = 180o 2(m + n) + 68o = 180o…(1) in (Delta) XOZ, m + n + q = 180o …(2) (m + n) = 180o – q…(3) substituting 180o – q for (m + n) in (1) gives 2(180o – q) + 68o = 180o 360o – 2q = 180o – 68o 360o – 2q = 112o 360o – 112o = 2q 248o = 2q q = (frac{248^o}{2}) = 124o hence, o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

In the diagram, (bar{OX}) bisects o, calculate the value of

  • A.
    68o
  • B.
    72o
  • C.
    112o
  • D.
    124o
Correct Answer: Option D
Explanation

In (Delta) XYZ, 2m + 2n + 68o = 180o
2(m + n) + 68o = 180o…(1)
in (Delta) XOZ, m + n + q = 180o …(2)
(m + n) = 180o – q…(3)
substituting 180o – q for (m + n) in (1) gives
2(180o – q) + 68o = 180o
360o – 2q = 180o – 68o
360o – 2q = 112o
360o – 112o = 2q
248o = 2q
q = (frac{248^o}{2})
= 124o
hence, o

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