In the diagram above, AB represents a uniform rod of length 1.50m which is in equilibrium on a pivot at P, If AP = 40cm, calculate the mass of the rod. [g = 10ms-2]
-
A.
0.280kg -
B.
0.400kg -
C.
0.613kg -
D.
0.800kg
Correct Answer: Option D
Explanation
m = (frac{0.7 times 40}{35} = 0.8kg)