In a series R-L-C circuit, R = 10(Omega), (X_{c})= 4(Omega) and (X_{L}) = 9(Omega). The impedance of the circuit is
-
A.
4.1(Omega) -
B.
5.0(Omega) -
C.
10.8(Omega) -
D.
11.2(Omega)
Correct Answer: Option D
Explanation
The impedance for a RLC circuit is
(Z = sqrt{R^{2} + (X_{L} – X_{C})^{2}})
= (sqrt{10^{2} + (9 – 4)^{2}})
= (sqrt{125})
= 11.18(Omega) (approxeq) 11.2(Omega)