If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600 µC across the field is?
-
A.
0.8 J -
B.
1.8 J -
C.
9.0 J -
D.
18.0 J
Correct Answer: Option B
Explanation
Work done = product of the charge Q, and the p.d V.
(i)/e work done = Q.V = 600 x 10-6 x 3.0 x 10-3 = 1.8 J.