If the fundamental frequency of a closed pipe organ on a day when the speed...

If the fundamental frequency of a closed pipe organ on a day when the speed of sound is 340ms^-1 is 170Hz, then the length of the pipe is

(lambda) = (frac{v}{f})
= (frac{340}{170})
= 2m ; for closed pipe
L = (frac{1}{4})(lambda)
= (frac{1}{4}) x (frac{2}{1})
= 0.5m
= 50cm

If the fundamental frequency of a closed pipe organ on a day when the speed…