If (log_{10}y + 3log_{10}x geq log_{10}x), express y in terms of x.
-
A.
(y geq frac{1}{x}) -
B.
(y leq frac{1}{x}) -
C.
(y leq frac{1}{x^{2}}) -
D.
(y geq frac{1}{x^{2}})
Correct Answer: Option D
Explanation
(log_{10}y + 3log_{10}x geq log_{10}x)
(implies log_{10}y geq log_{10}x – 3 log_{10}x )
(log_{10}y geq -2log_{10}x = log_{10}y geq log_{10}x^{-2})
(log_{10}y geq log_{10}(frac{1}{x^{2}}) implies y geq frac{1}{x^{2}})