If log318 + log33 – log3x = 3, Find x.
-
A.
1 -
B.
2 -
C.
o -
D.
3
Correct Answer: Option B
Explanation
log(_{3}^{18}) + log(_{3}^{3}) – log(_{3}^{x}) = 3
log(_{3}^{18}) + log(_{3}^{3}) – log(_{3}^{x}) = 3log33
log(_{3}^{18}) + log(_{3}^{3}) – log(_{3}^{x}) = log333
log3((frac{18 times 3}{X})) = log333
(frac{18 times 3}{X}) = 33
18 x 3 = 27 x X
x = (frac{18 times 3}{27})
= 2