Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied [Specific latent heat of fusion of ice = 336(Jg^{-1})]
-
A.
2400J -
B.
6800J -
C.
7251J -
D.
24000J
Correct Answer: Option D
Explanation
The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)
Q = (50 times 336 = 16800J) but this is 70% of the total heat supplied so that we have,
70% total heat = 16800J
(frac{70}{100}) of total heat = 16800J
⇒ Total heat supplied = (frac{16800times100}{70} = 24000J)