Given that sin (P = frac{5}{13}), where p is acute, find the value of cos p – tan p
-
A.
(frac{79}{156}) -
B.
(frac{85}{156}) -
C.
(frac{7}{13}) -
D.
(frac{8}{1})
Correct Answer: Option A
Explanation
If (sin P = frac{5}{13}) from right angled triangle from pythagoras theorem
(BC^2 = 13^2 – 5^2\
=169-25\
BC = sqrt{144} = 12\
∴ cos P – tan P = frac{12}{13} – frac{5}{12}\
=frac{79}{156})