Given that 32.0g sulphur contains 6.02 x 10 23 sulphur atoms how many atoms are there in 2.70g of aluminium? {Al = 27, S =32}
-
A.
6.02 x 10 23 -
B.
3.01 x 1022 -
C.
6.02 x 1022 -
D.
5. 08 x 1022 -
E.
3.01 x 1022
Correct Answer: Option C
Explanation
27g Aluminium = (6.02 times 10^{23})
1g Al = (frac{6.02 times 10^{23}}{27})
2.7g Al = (frac{6.02 times 10^{23}}{27} times 2.7)
= (6.02 times 10^{22} Al ) atoms