Find the 6th term of the sequence (frac{2}{3} frac{7}{15} frac{4}{15}),…
-
A.
-(frac{1}{3}) -
B.
-(frac{1}{5}) -
C.
-(frac{1}{15}) -
D.
(frac{1}{9})
Correct Answer: Option A
Explanation
a = (frac{2}{3}), d = (frac{7}{15}) – (frac{2}{3})
= 7 – 10
= (frac{-3}{15})
d = – (frac{-1}{5})
T6 = a + 5d
= (frac{2}{3}) + 5((frac{-1}{5})
= (frac{2}{3}) – 1
= (frac{2 – 3}{3})
= (frac{-1}{3})