Factorize completely 81a4 – 16b4

Factorize completely 81a4 – 16b4

  • A.
    (3a + 2b)(2a – 3b)(9a2 + 4b2)
  • B.
    (3a – 2b)(2a – 3b)(4a2 – 9b2)
  • C.
    (3a – 2b)(3a + 2b)(9a2 + 4b2)
  • D.
    (6a – 2b)(8a – 3b)(4a3 – 9b2)
Correct Answer: Option C
Explanation

81a4 – 16b4 = (9a2)2 – (4b2)2
= (9a2 + 4b2)(9a2 – 4b2)
N:B 9a2 – 4b2 = (3a – 2b)(3a + 2b)

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