Evaluate (int^{2} _{3}(x^2 – 2x)dx)
-
A.
4 -
B.
2 -
C.
4/3 -
D.
1/3
Correct Answer: Option C
Explanation
(int^{2} _{3}(x^2 – 2x)dx\=left[frac{x^3}{3}-frac{2x^2}{2}right ]^{2}_{3}\left[frac{x^3}{3}-x^2 + Cright ]^{2}_{3}\left[frac{3^3}{3}-3^2 + C right ]-left[frac{2^3}{3}-2^2 + C right ]\9-9-left[frac{8}{3}-4 right ]\=frac{-8}{3}+4\=frac{4}{3})