Consider the equation below: Cr(_2)O(_7 ^{2-}) + 6Fe(^{2+}) + 14H(^{+}) (to) 2Cr(^{3+}) + 6Fe(^{3+}) +...

Consider the equation below:

Cr(_2)O(_7 ^{2-}) + 6Fe(^{2+}) + 14H(^{+}) (to) 2Cr(^{3+}) + 6Fe(^{3+}) + 7H(_2)O.

The oxidation number of chromium changes from

Cr(_2)O(_7 ^{2-}) + 6Fe(^{2+}) + 14H(^{+}) (to) 2Cr(^{3+}) + 6Fe(^{3+}) + 7H(_2)O

The oxidation of Cr in Cr(_2)O(_7 ^{2-}) :

Let the oxidation of Cr = x;

2x + (-2 x 7) = -2 (implies) 2x – 14 = -2

2x = 12 ; x = +6

Hence, the change in oxidation of Cr = +6 to +3

There is an explanation video available below.

Consider the equation below: Cr(_2)O(_7 ^{2-}) + 6Fe(^{2+}) + 14H(^{+}) (to) 2Cr(^{3+}) + 6Fe(^{3+}) +…