Calculate the temperature of 6 moles of an ideal gas at a pressure of 7.6 x 106Nm-2 with a volume of 10-3m3.
[R = 8.3jmol-1K-1]
[R = 8.3jmol-1K-1]
-
A.
201oC -
B.
126oC -
C.
153oC -
D.
185oC
Correct Answer: Option C
Explanation
T = (frac{PV}{nR}) = (frac{7.6 x 10^6 x 10^-3}{6 x 8.3})
= 153oC
There is an explanation video available below.