Calculate the amount of heat required to convert 2kg of ice at 2oC to water at 0oC. [specific heat capacity of ice = 2090Jkg-1oC-1, specific latent heat of fusion of ice = 333kJkg-1]
-
A.
666J -
B.
8360J -
C.
666 000J -
D.
674 360J
Correct Answer: Option D
Explanation
Q = mL + mc(theta)
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J