(begin{array}{c|c} text{Class Interval} & 1 – 5 & 6 – 10 & 11 – 15…

(begin{array}{c|c} text{Class Interval} & 1 – 5 & 6 – 10 & 11 – 15 & 16 – 20 & 21 – 25 \ hline Frequency & 6 & 15 & 20 & 7 & 2end{array})
Estimate the median of the frequency distribution above
  • A.
    10(frac{1}{2})
  • B.
    11(frac{1}{2})
  • C.
    12
  • D.
    13
Correct Answer: Option C
Explanation

Median = L + [(frac{frac{N}{2} – f}{fm})]h
N = Sum of frequencies
L = lower class boundary of median class
f = sum of all frequencies below L
fm = frequency of modal class and
h = class width of median class
Median = 11 + [(frac{frac{50}{2} – 21}{20})]5
= 11 + ((frac{25 – 21}{20}))5
= 11 + ((frac{(4)}{20}))
11 + 1 = 12

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