An organic compound has the empirical formula (CH_{2}). If its molar mass is 42(gmol^{-1}), what is its molecular formula? (C = 12.0, H = 1.0)
-
A.
(C_{2}H_{4}) -
B.
(C_{3}H_{4}) -
C.
(C_{3}H_{6}) -
D.
(C_{4}H_{8})
Correct Answer: Option C
Explanation
Given the molecular formula, (CH_{2}).
The empirical formula will be ((CH_{2})n)= 42
((12+(2times1))n =42)
⇒ (14n =42)
n = 3, hence the empirical formula is (C_{3}H_{6})