An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral displacement of the object if the refractive index of the glass is 1.5.
-
A.
1.0cm -
B.
1.5cm -
C.
2.0cm -
D.
2.5cm
Correct Answer: Option A
Explanation
1.5 = (frac{3}{text {apparent displacement}})
Apparent depth = 2cm
displacement = 3 – 2
= 1cm