An object is moving with a velocity of 5m-1. At what height must a similar body be situated to have a potential energy equal in value with kinetic energy of the moving body?
-
A.
25.0m -
B.
20.0m -
C.
1.3m -
D.
1.0m
Correct Answer: Option C
Explanation
P.E = K.E
Therefore, h = (frac{v^2}{2g} = frac{5^2}{2 times 10})
= 1.25
Approx 1.3 (C)
There is an explanation video available below.