An element Z contains 80% of (^{16} _8)Z and 20% of (^{18} _8)Z. Its relative atomic mass is
-
A.
16.2 -
B.
17.6 -
C.
16.0 -
D.
16.4
Correct Answer: Option D
Explanation
R.A.M of Z = (16(frac{80}{100}) + 18(frac{20}{100}))
= (12.8 + 3.6)
= 16.4
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