An electron enters perpendicularly into a uniform magnetic field which has a flux density of 0.12 T This results in a magnetic force of 9.6 x 10(^{-2}) N on the electron. Calculate the speed of the electron as it enters the magnetic field. (e =1.6 x (10^{19}) C)
Explanation
F = evB sin (theta)
V = (frac{F}{evB sin theta} = frac{9.6 times 10^{12}}{1.6 times 10^{-19} times 0.12 sin 90^o})
= (frac{9.6 times 10^{-12}}{1.6 x 10^{-19} times 0.12 times 1})
= 5.0 x 10(^8 ms{-1})