An arrow of mass 0.1kg moving with a horizontal velocity of 15ms-1 is shot into a wooden block of mass 0.4kg lying at rest on a smooth horizontal surface. Their common velocity after impact is
-
A.
15.0 ms-1 -
B.
7.5 ms-1 -
C.
3.8 ms-1 -
D.
3.0 ms-1
Correct Answer: Option D
Explanation
M1U1 + M2U2
= (m1 + m2)v
= (frac{(0.1 {times} 15) + (0.4 {times} 0)}{(0.1 + 0.4)})
v = 3ms-1