A wire of length 5.0 m and diameter 2.0 mm extends by 0.25 mm when a force of 50 N was used to stretch it from its end. Calculate the;
(a) stress on the wire;
(b) strain in, the wire. [(pi = 3.142)]
Explanation
(a) Stress = (frac{Force}{Area} = frac{50}{3.142(1 times 10^{-3})^2})
(b) Strain = (frac{extension}{length} = frac{2.5 times 10^{-5}}{5})
= 5 x 10(^{-5})