A water fall is 420m high. Calculate the difference in temperature of the water between the top and bottom of the water fall. Neglect heat loses(g = 10.0m-2 specific heat capacity of water = 4.20 x 10-3 JKg-1 K-1)
-
A.
0.1oC -
B.
1.0oC -
C.
42oC -
D.
100oC -
E.
4.20oC
Correct Answer: Option B
Explanation
Potential Energy = Heat Energy
mgh = Mc(Delta theta = frac{gh}{c} = frac{10 times 240}{4.20 times 10^3})
= 1.0oC