A trough 12.0cm deep is filled with water of refractive index (frac{4}{3}). By how much would a coin at the bottom of the trough appear to be displaced when viewed vertically from above the water surface?
-
A.
3.0cm -
B.
6.0cm -
C.
9.0cm -
D.
16.0cm
Correct Answer: Option A
Explanation
(frac{4}{3}) = (frac{12}{text {Apparent depth}})
Apparent depth = 9cm
Height by which coin is raised = 12 – 9
= 3cm