A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms(^{-2})]
-
A.
0.04m -
B.
0.12m -
C.
0.01m -
D.
0.08m
Correct Answer: Option D
Explanation
From Hoke’s Law, F = ke, K = Constant of Force
For he first case, Force = mg,
= 0.8 × 10 = 8N
∴ 8 = k × 0.04
k = (frac{8}{0.04})
= (frac{200N}{m})
Since K is constant
For the second case, F = ke
F = 200 × e
∴ e = (frac{F}{200})
= (frac{16}{200})
= 0.08m
There is an explanation video available below.