A projectile is fired from the ground level with a velocity of 300ms-1 at an angle of a 30o to the horizontal.
Calculate the time taken to reach the maximum height?
[g = 10ms-2]
-
A.
30s -
B.
20s -
C.
25s -
D.
15s
Correct Answer: Option D
Explanation
The total time of flight is given as
(T = frac{2usintheta}{g})
Hence, time to maximum height is half of the total time of flight,
t = (frac{u sintheta}{g})
= (frac{300 text {sin} 30}{10}) = 15s
There is an explanation video available below.