A piece of copper of mass 30g loses 60J of heat energy. If the specific heat capacity of copper is 400J(kg^{-1}K^{-1}), Calculate the change in the temperature of the copper
-
A.
0.2K -
B.
0.8K -
C.
2K -
D.
4.5K -
E.
5K
Correct Answer: Option E
Explanation
H=(mcDeltatheta Rightarrow 60=0.03times400timesDeltatheta\60= 12Deltatheta therefore Deltatheta=60/12 =5K)